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The variation of interatomic energy with atomic distance is given by the following equation V(r)=4ε Where V(r) is the potential energy, and r is interatomic distance. ε and σ are constant. Find the value of energy at the point where the interatomic force is zero?

The variation of interatomic energy with atomic distance is given by the following equation V(r)=4ε Where V(r) is the potential energy, and r is interatomic distance. ε and σ are constant. Find the value of energy at the point where the interatomic force is zero? Correct Answer Where V(r) is the potential energy, and r is interatomic distance. ε and σ are constant. Find the value of energy at the point where the interatomic force is zero? ] – ε

or minimum energy => d(V(r))/d(r)=0 => d]/dr=0 => 4 ε => 4ε(1/4-1/2) => -ε.

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