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The ultraviolet spectrum of benzonitrile shows a secondary absorption band at 271 nm. If a solution of benzonitrile in water, with a concentration of 1×10-4 molar solution is examined at 271 nm, what will be the absorbance reading (ℇ = 1000) and what will be the intensity ratio, IO/I, respectively?

The ultraviolet spectrum of benzonitrile shows a secondary absorption band at 271 nm. If a solution of benzonitrile in water, with a concentration of 1×10-4 molar solution is examined at 271 nm, what will be the absorbance reading (ℇ = 1000) and what will be the intensity ratio, IO/I, respectively? Correct Answer 0.1, 1.26

A = ℇCl and ℇ = 1000 (Given) A = 1000 x 1 x10-4 x 1 A = 0.1 Also, A = log (IO/l) 0.1 = log (IO/I) => IO/I = 1.26.

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