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What is the monomer pair required for the formation of Nylon 610?

What is the monomer pair required for the formation of Nylon 610? Correct Answer hexamethylene diamine + sebacic acid

The reaction between hexamethylene diamine and sebacic acid gives the polyamide Nylon 610 via formation of an appropriate salt. The reaction is given by- nNH2−(CH2)6−NH2 + HOOC−(CH2)8−COOH → n.

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1. In early 1930's Nylon was prepared from coal, water and air.
2. Nylon was the first synthetic fibre.
3. Nylon fibre was strong elastic and light.
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