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Heat of fusion of benzene is 10 J at 0oC, if Cp of solid benzene is 10 J/oC, and that of liquid benzene is 5 J/oC what is the enthalpy change of benzene from – 10oC to 10oC?

Heat of fusion of benzene is 10 J at 0oC, if Cp of solid benzene is 10 J/oC, and that of liquid benzene is 5 J/oC what is the enthalpy change of benzene from – 10oC to 10oC? Correct Answer 160 J

∆H = -10∫010.dT + 10 + 0∫105.dT = 10*10 + 10 + 5*10 = 160 J.

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