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50 Kg of a solid liquid mixture containing 20% solid and 80% water is left open in the atmosphere, after some time the water is 60%, how much water is evaporated?

50 Kg of a solid liquid mixture containing 20% solid and 80% water is left open in the atmosphere, after some time the water is 60%, how much water is evaporated? Correct Answer 25 Kg

Let the weight of the water evaporated be W. Water Balance: 0.8(50) = 1(W) + 0.6(50 – W), => W = 25 Kg.

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