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The rate of flow in stream with 20% CH4 and 80% H2O is 5 mole/hr, the contained was initially filled with 3 mole of H2O, what will be the percentage of CH4 in product stream?

The rate of flow in stream with 20% CH4 and 80% H2O is 5 mole/hr, the contained was initially filled with 3 mole of H2O, what will be the percentage of CH4 in product stream? Correct Answer 12.5

Percentage of CH4 = 1/(1 + 4 + 3)*100 = 12.5%.

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