Iron is corroding at a current density of 1.69*10-4 amp/cm2. What would be the corrosion rate in MDD?

Iron is corroding at a current density of 1.69*10-4 amp/cm2. What would be the corrosion rate in MDD? Correct Answer 423

We know MDD = W/At = (I*am) / (n*F). We should convert the given unit values in milligrams/sq. Decimeter/day. Given, I = 1.69*10-4 amp/cm2 Atomic weight of iron = am = 55.86 g/mol n = number of electrons = 2 F = faraday’s constant = 96500 coulombs = (1.96×10-4 coulombs/sec*cm2) × (55.86) ÷ (2×96500 coulombs) = / = 422.53 MDD.

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