Related Questions

If you add up the digits of a three -digit number you get 18 . The ten's digit is twice the hundred's digit and the hundred's digit is 13 the unit's digit. What is the number?
A 246
B 369
C 531
D 855
In a two digit number, if it is known that its unit's digit exceeds its ten's digit by 2 and that product of the given number and the sum of its digits is equal to 144, then the number is-
A 46
B 42
C 26
D 24
In a two-digit number, if it is known that its unit's digit exceeds its tens digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is ---
A 46
B 42
C 26
D 24
How many 5 digit numerals have 9 as the first digit, 3 or 6 as the third digit, and no digit repeated?
A 672
B 762
C 572
D 567
How many 5-digit numerals have 9 as the first digit, 3 or 6 as the third digit, and no digit repeated?
A 672
B 762
C 572
D 567
A two-digit number has 3 in its unit digit. The sum of its digit is one-seventh of the number itself. What is the number?
A 73
B 63
C 53
D 83
In a two digit number, the digit in the unit's place is two more than the three times of the digit in ten's place . If the sum of the tow digits is 6 , the number is -
A 51
B 24
C 15
D 42
If the digit in the unit's place of a two-digit number is halved and the digit in the ten's place is doubled, the number thus obtained is equal to the number obtained by interchanging the digits. Which of the following is definitely true ?
A Sum of the digits is a two-digit number
B Digit in the unit's place is half of the digit in the ten's place
C Digit in the unit's place and the ten's place are equal
D Digit in the unit's place is twice the digit in the ten's place
Scheme-1: C6H5N2Cl→CuCNC6H5CN→H2o/H+C6H5COOH→∆Product-I Scheme-2: C6H5NO2→Fe/HCLC6H5NH2→N2NO3+HCL, 273KC6H5N2Cl→H2O/H+Product-II Scheme-3: CH3COOH→NH3CH3CONH2→NaOBrProduct-III উল্লিখিত Scheme সমূহে Product-I, Product-II এবং Product-III হলো যথাক্রমেঃ
A C6H5COONH4, C6H5Cl and CH3OH
B C6H5CONH2, C6H5NH2 and CH3OH
C C6H5CONH2, C6H5NH2 and CH3NH2
D C6H5CONH2, C6H5OH and CH3OH
A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4- digit number 13b7, which is divisible by 11. Then, (a+b)=?
A 10
B 11
C 12
D 15

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