A two-digit number has 3 in its unit digit. The sum of its digit is one-seventh of the number itself. What is the number?
A
73
B
63
C
53
D
83
Correct Answer: 63
Since it is in the form of a two digit number, then we can write it as a decimal expansion with a three in the units place.Let y = 10x + 3We also know that x + 3 = y⋅17x + 3 = y⋅17This means if we multiply both sides by 7 we get:y = 7(x + 3)y = 7(x + 3)y = 7x + 21y = 7x + 21Since these are both equal to y, we can set them equal one another to find x, the tens digit value:7x + 21 = 10x + 37x + 21 = 10x + 3−3x + 21 = 3−3x + 21 = 3−3x = −18−3x = −18x = 6x = 6y = 10x + 3 = 10(6) + 3 = 63