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What is the value of C.O.P. in the following diagram?

What is the value of C.O.P. in the following diagram? Correct Answer 210 Q / m1 (h2 – h1) + m2 (h6 – h5)

As m1 flows through the low-temperature cascade system. So, when it passes through the evaporator i.e. between point 1 and point 4, there is change in enthalpy which produces the refrigeration effect. Hence, R.E. = m x delta h = 210 Q where, Q is the load on the low-temperature cascade system in tones of refrigeration Work = mass of refrigerant flowing through the compressor x change of enthalpy Work done by low-temperature cascade system = m1 (h2 – h1) Work done by high-temperature cascade system = m2 (h6 – h5) Total work = Work done by low-temperature cascade system + Work done by high-temperature cascade system Total work done = m1 (h2 – h1) + m2 (h6 – h5) As, C.O.P. = Refrigeration effect / Total work done = 210 Q / m1 (h2 – h1) + m2 (h6 – h5).

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