The frictional torque transmitted in a conical pivot bearing, considering uniform wear, is
A
1/2 × μ.W. R cosec α
B
2/3 × μ.W. R cosec α
C
3/4 × μ.W. R cosec α
D
μ.W.R cosec α
Correct Answer: 1/2 × μ.W. R cosec α
Total frictional torqur = 1/2 × μ.W. R cosec α where R = Radius of the shaft, and α = Semi-angle of the cone.