The maximum efficiency of a screw jack is
A
1 – sinφ/ 1 + sinφ
B
1 + sinφ/ 1 – sinφ
C
1 – tanφ/ 1 + tanφ
D
1 + tanφ/ 1 – tanφ
Correct Answer: 1 – sinφ/ 1 + sinφ
Maximum efficiency, ηmax = sin (90º – φ + φ) – sinφ/sin (90º – φ + φ) + sinφ = sin 90º – sin φ/sin 90º + sin φ = 1 – sinφ/ 1 + sinφ.