The efficiency of a screw jack is maximum, when (where $$\alpha $$ = Helix angle and $$\varphi $$ = Angle of friction)
A
$$\alpha = {45^ \circ } + \frac{\varphi }{2}$$
B
$$\alpha = {45^ \circ } - \frac{\varphi }{2}$$
C
$$\alpha = {90^ \circ } + \varphi $$
D
$$\alpha = {90^ \circ } - \varphi $$
Correct Answer: $$\alpha = {45^ \circ } - \frac{\varphi }{2}$$