Angular acceleration of a link can be determined by dividing the

A centripetal component of acceleration with length of link
B tangential component of acceleration with length of link
C resultant acceleration with length of link
D all of the mentioned

Correct Answer: tangential component of acceleration with length of link

The angular acceleration of the link AB is obtained by dividing the tangential components of the acceleration of B with respect to A to the length of the link.
Bissoy MCQ
#Machine Kinematics #Properties of Instantaneous Centre

Related Questions

In a drag link quick return mechanism, the shortest link is always fixed. The sum of the shortest and longest link is
A equal to sum of other two
B greater than sum of other two
C less than sum of other two
D none of the mentioned
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B tangential component only
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A vBA × AB
B $$\frac{{{\text{vBA}}}}{{{\text{AB}}}}$$
C v2BA
D $$\frac{{{{\text{v}}^2}{\text{BA}}}}{{{\text{AB}}}}$$
A figure was reached by first multiplying a number by 4 and then dividing the product by 100. The figure can be obtained by dividing the original number by
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On dividing a number by 357, we get 39 as remainder. On dividing the same number by 17, what will be the remainder?
A 3
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A 35/5
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গরম বাতাসে পরিপূর্ণ M ভরের একটি বেলুন (থ্রডি সহ) পৃথিবীর দিকে খুব ত্বরণ a তে নেমে আসছে। ঝুড়ি থেকে কি পরিমান m ভর ফেলে দিলে বেলুনটি উপরের দিকে একই খুব ত্বরন a- তে উঠে যাবে ? সকল ক্ষেত্রে বেলুনটির আয়তন একই ছিল বলে ধরে নেওয়া হলো। (g = অভিকর্ষীয় ত্বরন)(A hot air balloon with a bucket is descending towards the earth with a constant acceleration a. The combined mass of the balloon and bucket is M. What mass m from the bucket should be released so that the balloon starts ascending up with the same acceleration a? Consider the volume of the balloon remains constant at all the time. (g=acceleration due to gravity))
A m=2ag+aM
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D none of the mentioned

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