If a simple pendulum oscillates with an amplitude 50 mm and time period 2s, then its maximum velocity is

If a simple pendulum oscillates with an amplitude 50 mm and time period 2s, then its maximum velocity is Correct Answer 0.15 m/s

Maximum velocity vmax = ωA where ‘ω’ is the angular frequency and ‘A’ is the amplitude. Therefore vmax = (2π/T)A = (2π/2)×50×10-3 = 0.157 m/s.

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The two simple pendulum A and B are similar and have different time period but equal amplitude. If the time period of pendulum A is more than pendulum B, then: