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With variable thermal conductivity, Fourier law of heat conduction through a plane wall can be expressed as

With variable thermal conductivity, Fourier law of heat conduction through a plane wall can be expressed as Correct Answer Q = -k0 (1 + β t) A d t/d x

Here k0 is thermal conductivity at zero degree Celsius.

Related Questions

Fourier's law of heat conduction is (where Q = Amount of heat flow through the body in unit time, A = Surface area of heat flow, taken at right angles to the direction of heat flow, dT = Temperature difference on the two faces of the body, dx = Thickness of the body, through which the heat flows, taken along the direction of heat flow, and k = Thermal conductivity of the body)
Fourier's law of heat conduction is (where Q = Amount of heat flow through the body in unit time, A = Surface area of heat flow, taken at right angles to the direction of heat flow, dT = Temperature difference on the two faces of the body, dx = Thickness of the body, through which the heat flows, taken along the direction of heat flow and k = Thermal conductivity of the body)
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