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Calculate the volume of the aeration tank required for the following data: Flow: 800 m3/d BOD: 1000 mg/L F/M ratio: 0.15(extended aeration) MLSS: 3500 mg/L

Calculate the volume of the aeration tank required for the following data: Flow: 800 m3/d BOD: 1000 mg/L F/M ratio: 0.15(extended aeration) MLSS: 3500 mg/L Correct Answer 1550 m3

The BOD load is calculated as Flow x BOD. Since the flow is in m3/d, the m3 is converted to L by multiplying by 1000. BOD load is expressed as Kg/L by dividing it by 1000000. BOD load = 800 x 1000 x 1000/ (1000×1000) = 800 Kg/d. Then Volume of tank = Biomass/MLSS. Biomass = BOD load/F/M. MLSS is converted to kg/ m3. Thus biomass= 800/ 0.15 =5333.3Kg. MLSS = 3.5 Kg/m3. Volume of tank = 5333.33/3.5 = 1523.81 m3. (Rounded off 1550 m3).

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