Calculate the magnitude of capillary effect in millimeters in a glass tube of 7mm diameter, when immersed in mercury. The temperature of the liquid is 25℃ and the values of surface tension of mercury at 25℃ is 0.51 N/m. The angle of contact for mercury is 130°.

The value of :
$$\left( {\frac{{0.051 \times 0.051 \times 0.051 + 0.041 \times 0.041 \times 0.041}}{{0.051 \times 0.051 - 0.051 \times 0.041 + 0.041 \times 0.041}}} \right)$$

A

0.00092

B

0.0092

C

0.092

D

0.92

The depth of centre of pressure (h) for a vertically immersed surface from the liquid surface is given by (where IG = Moment of inertia of the immersed surface about horizontal axis through its centre of gravity, A = Area of immersed surface, and x = Depth of centre of gravity of the immersed surface from the liquid surface)

A

(IG/Ax̅) - x̅

B

(IG/x̅) - Ax̅

C

(Ax̅/IG) + x̅

D

(IG/Ax̅) + x̅

The depth of centre of pressure (h) for a vertically immersed surface from the liquid surface is given by (where $${I_{\text{G}}}$$ = Moment of inertia of the immersed surface about horizontal axis through its centre of gravity, A = Area of immersed surface and x = Depth of centre of gravity of the immersed surface from the liquid surface)

A

$$\frac{{{I_{\text{G}}}}}{{{\text{A}}\overline {\text{x}} }} - \overline {\text{x}} $$

B

$$\frac{{{I_{\text{G}}}}}{{\overline {\text{x}} }} - {\text{A}}\overline {\text{x}} $$

C

$$\frac{{{\text{A}}\overline {\text{x}} }}{{{I_{\text{G}}}}} + \overline {\text{x}} $$

D

$$\frac{{{I_{\text{G}}}}}{{{\text{A}}\overline {\text{x}} }} + \overline {\text{x}} $$

Consider a capillary tube in which water has risen. The contact angle is θ. The radius of the capillary tube is ‘r’. The surface tension is ‘S’. And the density of water is ‘ρ’. What is the expression for the height of water risen in the tube? Assume the radius of meniscus to be ‘R’. Let the height of water risen in the tube be ‘h’.

A

2Ssinθ / Rρg

B

2S / Rρg

C

2Scosθ / Rρg

D

2S / rρg

The angle of contact between a glass capillary tube of length 10 cm and a liquid is 90 degree . If the capillary tube is dipped vertically in the liquid, then the liquid:

A

Will rise in the tube

B

Will get depressed in the tube

C

Will rise -up to 10 cm in the tube and will over flow

D

Will neither rise nor fall in the tube.

The angle of contact between a glass capillary tube of length 10 cm and a liquid is 90 Degree. If the capillary tube is dipped vertically in the liquid, then the liquid:

A

Will rise in the tube

B

Will get depressed in the tube

C

Will rise-up to 10 cm in the tube and will over flow

D

Will neither rise not fall in the tube

If a glass tube of 10 mm diameter is immersed in water, what will be the rise or fall in capillary? (Take surface tension = 0.075 N/m, g = 10 m/s2 and angle of contact = 0)

A

0.75

B

1.5

C

3

D

6

A glass tube of small diameter (d) is dipped in fluid. The height of rise or fall in the tube given by (where w = Specific weight of liquid, α = Angle of contact of the liquid surface, and σ = Surface tension)

A

4wd/σ cosα

B

σ cosα/4wd

C

4σ cosα/wd

D

wd/4σ cosα

A glass tube of small diameter (d) is dipped in fluid. The height of rise or fall in the tube given by (where w = Specific weight of liquid, $$\alpha $$ = Angle of contact of the liquid surface and $$\sigma $$ = Surface tension)

A

$$\frac{{4{\text{wd}}}}{{\sigma \cos \alpha }}$$

B

$$\frac{{\sigma \cos \alpha }}{{4{\text{wd}}}}$$

C

$$\frac{{4\sigma \cos \alpha }}{{{\text{wd}}}}$$

D

$$\frac{{{\text{wd}}}}{{4\sigma \cos \alpha }}$$

Capillary rise of mercury in a small diameter tube is proportional to (where, d = diameter of the tube, σ = surface tension of mercury)

A

d

B

$$\frac{1}{{\text{d}}}$$

C

$$\sigma $$

D

$$\frac{l}{\sigma }$$

Calculate the magnitude of capillary effect in millimeters in a glass tube of 7mm diameter, when immersed in mercury. The temperature of the liquid is 25℃ and the values of surface tension of mercury at 25℃ is 0.51 N/m. The angle of contact for mercury is 130°.

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