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The electric field intensity of a surface with permittivity 3.5 is given by 18 units. What the field intensity of the surface in air?

The electric field intensity of a surface with permittivity 3.5 is given by 18 units. What the field intensity of the surface in air? Correct Answer 63

The relation between flux density and permittivity is given by En1/En2 = ε2/ ε1. Put En1 = 18, ε1 = 3.5 and ε2 = 1. We get En2 = 18 x 3.5 = 63 units.

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