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What is the coupling factor if self-inductances and mutual inductance are 5.096 H, 0.05098 H and 0.5096 H respectively?

What is the coupling factor if self-inductances and mutual inductance are 5.096 H, 0.05098 H and 0.5096 H respectively? Correct Answer 1

Coupling factor is calculated by the ratio of mutual inductance with square root of product of respective self-inductances. That is, k = M/ √(L1L2) = 0.5096 /√(5.096 * 0.05098) = 0.9999 =1.

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