In theis diagram AB=AC angle A = 40 degree and BD is perpendicular to AC at D. how many degrees are there in angle DBC?
A
20 degree
B
40 degree
C
50 degree
D
70 degree
Correct Answer: 20 degree
△ABC এ AB = AC,∠B = ∠C∴∠A + ∠B + ∠C = 180∘⇒∠B + ∠C = 180∘ - 40∘⇒∠B + ∠C = 140∘⇒2∠B = 140∘∴∠B = 70∘ = ∠CAgain, △ABD এ ∠ADB = 90∘∠A = 40∘∴∠DBA = 180∘ - 90∘ - 40∘ = 50∘ ∴∠DBC = ∠ABC - ∠DBA = 70∘ - 50∘ = 20∘