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A single-phase semi-converter is connected to a 230 V source and is feeding a load R = 10 Ω in series with a large inductance that makes the load current ripple free. For α = 45°, find the rectification efficiency. The RMS value of output voltage is 219.3 V

A single-phase semi-converter is connected to a 230 V source and is feeding a load R = 10 Ω in series with a large inductance that makes the load current ripple free. For α = 45°, find the rectification efficiency. The RMS value of output voltage is 219.3 V Correct Answer 80.58 %

Vo =( Vm/π) (1 + cosα) = 176.72V Io = Vo/R Irms = Io = Vo/R = 17.67 A Vrms = 219.3 V (given) η = (Vo x Io) / (Vrms X Irms) = 0.8058 = 80.58 %.

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