For the initially relaxed circuit shown below, the Laplace transform of the KVL when the switch is closed is I(s) = Vs/s The value of X is

For the initially relaxed circuit shown below, the Laplace transform of the KVL when the switch is closed is I(s) = Vs/s The value of X is Correct Answer X

When switch is closed, Ldi/dt + 1/C ∫ idt = Vs Laplace of the above gives, L + 1/C = Vs/s.
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