A eutectoid steel is slowly cooled from a temperature of 750°C to a temperature just below 727°C. Calculate the percentage of ferrite and cementite.

A eutectoid steel is slowly cooled from a temperature of 750°C to a temperature just below 727°C. Calculate the percentage of ferrite and cementite. Correct Answer 88.3% and 11.7%

Eutectoid composition – 0.8% of Carbon, Ferrite composition- 0.025% of Carbon and cementite – 6.67% C. Apply the lever rule to get the percentages as % of Ferrite = 100(6.67 – 0.80)/(6.67 – 0.025)=88.3% ferrite %of Cementite = 100(0.80 – 0.025)/(6.67 – 0.025) =11.7%.

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