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What is the strain on a hanging load, when a force of 5 Newton is applied on it and it expands the length of the object from 8cm to 12 cm?

What is the strain on a hanging load, when a force of 5 Newton is applied on it and it expands the length of the object from 8cm to 12 cm? Correct Answer 0.5

GiveForce applied=5 N Original length(o)=8cm New length=12 cm Extended length(e)=New length-Original length Extended length(e)=12-8=>4cm Strain (s) = Extended length(e)/Original length(o) Strain (s)=4cm/8cm=>0.5.

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