Let us assume x (t) = A cos(ωt + φ), what is the value of k1 by considering θ (ω) is? b) A/2|H(jω)|ej c) |H(jω)|e-j d) A/2 |H(jω)|e-j
Let us assume x (t) = A cos(ωt + φ), what is the value of k1 by considering θ (ω) is? b) A/2|H(jω)|ej c) |H(jω)|e-j d) A/2 |H(jω)|e-j Correct Answer θ (ω)+Ø
The expression of k1 becomes K1 = A/2|H(jω)|ej. We obtain the steady state solution for y(t) by taking the inverse transform ignoring the terms generated by the poles of H(s).
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Feb 20, 2025