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Determine the voltage across (2+j5) Ω impedance considering 20∠30⁰ voltage source.

Determine the voltage across (2+j5) Ω impedance considering 20∠30⁰ voltage source. Correct Answer 46.69∠110.72⁰

The voltage across (2+j5) Ω impedance considering 20∠30⁰ voltage source is V2 = 8.68∠42.53o (2+j5) = 46.69∠110.72⁰V.

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