One can’t define an array without any constraints in VHDL.

One can’t define an array without any constraints in VHDL. Correct Answer False

We can define an array without any constraints in VHDL. When there are no constraints in array then it can have any number of elements. For example, TYPE my_type IS ARRAY (RANGE <>) OF BIT; this declaration defines an array of BIT data type without any constraint on the number of elements in the array.

Related Questions

A teacher asked the class to subtract 5 from 75.70% of the class said: 25. Their work was shown as: \(\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} 7&5 \end{array}}\\ {\underline {\begin{array}{*{20}{c}}\ { - 5} \ \ \ &{} \end{array}} }\\ {\underline {\begin{array}{*{20}{c}} 2&5 \end{array}} } \end{array}\) Which of the following describes the most appropriate remedial action that the teacher should take to clarify this misconception?
To an addition problem, \(\begin{equation} \frac{ \begin{array}[b]{r} 56 \\ +38 \end{array} }{ } \end{equation}\)  a class 2 student responded as \(\begin{equation} \frac{ \begin{array}[b]{r} 56\\ +38 \end{array} }{ 84 } \end{equation}\)As a reflective mathematics teacher, what will be your reaction to the child's answer?