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Maximum Amplitude of an amplitude modulated 10V and minimum amplitude is 5V. Find its modulation index?

Maximum Amplitude of an amplitude modulated 10V and minimum amplitude is 5V. Find its modulation index? Correct Answer 0.33

We know, Modulation Index(µ) = (Vmax-Vmin)/(Vmax+Vmin), Where, Vmax = Maximum Amplitude of an amplitude modulated = 10V Vmin = Minimum amplitude of an amplitude modulated = 5V Therefore, µ = (10-5)/(10+5) = 0.33.

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