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Find the complement of the Boolean expression (A + B).(A + C).(A + D).

Find the complement of the Boolean expression (A + B).(A + C).(A + D). Correct Answer A’.(B’ + C’ + D’)

The steps to derive the solution are given below. Using Distributive law, (X + Y).(X + Z) = X + YZ = ((A + B).(A + C).(A +D))’ = (A + B.C.D)’ Using DeMorgan’s law twice we get, = A’.(B.C.D)’ = A’.(B’ + C’ + D’)

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