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Complement A.B + A.C’ + D’.E’.

Complement A.B + A.C’ + D’.E’. Correct Answer (A’ + B’.C).(D + E)

The steps to derive the solution are given below. Using the ordinary distributive law, X.Y + X.Z = X.(Y + Z) = (A.(B + C’) + D’.E’)’ Using DeMorgan’s law twice, we get = (A.(B +C’))’.(D’.E’)’ = (A’ + (B + C’)’).(D + E) = (A’ + B’.C).(D + E)

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