Calculate the HCV and NCV of the coal for the following data. Weight of the coal=0.8g Water equivalent of calorimeter=460g Weight of the water=2600g Rise in temperature=2.42oC Cooling corrections=0.052oC Fuse wire corrections=10 calories H=6% and assume latent heat of steam=600cal/g.

Calculate the HCV and NCV of the coal for the following data. Weight of the coal=0.8g Water equivalent of calorimeter=460g Weight of the water=2600g Rise in temperature=2.42oC Cooling corrections=0.052oC Fuse wire corrections=10 calories H=6% and assume latent heat of steam=600cal/g. Correct Answer 9131.4cal/g

We know the formula for HCV and that is -fuse wire corrections there W is the weight of the water and w is the water equivalent and t2 and t1 are the final and initial temperatures. Substitute the values to get the HCV and for NCV=HCV – (0.09H*latent heat of steam).

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While calculating HCV, if we need to apply the fuse wire, acid and cooling corrections then what is the formula for HCV? /weight of fuel b) HCV = /weight of fuel c) HCV = /weight of fuel d) HCV = /weight of fuel