The reverse saturation current of a diode at 25°C is 1.5 x 10-9A. What will be the reverse current at temperature 30°C?
The reverse saturation current of a diode at 25°C is 1.5 x 10-9A. What will be the reverse current at temperature 30°C? Correct Answer 2.12 x 10-9A
The equation relating final reverse saturation current (Io2) to initial reverse saturation current (Io1) is given by Io2 = 2(∆T/10)Io1 Where ∆T is temperature change Here ∆T = 5, Therefore, Io2 = 25/10 Io1 = 1.414 x 1.5 x 10-9A = 2.121 x 10-9A.