Find the area enclosed by the curve formed by iz3+z2–z+i=0.
Find the area enclosed by the curve formed by iz3+z2–z+i=0. Correct Answer π
Dividing the equation by i on both sides, z3-iz2+iz+1=0 ⇒ z2(z-i)+i(z-i)=0 ⇒ (z-i)(z2+i)=0 ⇒ z=i or z2=-i ⇒ |z|=|i|=1 or |z2|=|z|2=|-i|=1 ⇒ |z|=1 ⇒ circle of radius 1 is formed. Hence, area=π(12)=π.
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Feb 20, 2025