Find the cube root of 8i lying in the first quadrant of the complex plane.
Find the cube root of 8i lying in the first quadrant of the complex plane. Correct Answer i+√3
Let z3=8i⇒z3=-8i3⇒3=1. ⇒z/(-2i)=1 or ω or ω2⇒z=-2i or -2iω or -2iω2 ⇒z=-2i or i+√3 or i-√3 out of which i+√3 lies in the first quadrant.
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Feb 20, 2025
