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Find the value of ∫tan-1⁡(x)dx.

Find the value of ∫tan-1⁡(x)dx. Correct Answer xtan-1 (x) – 1⁄2 ln⁡(1 + x2)

Add constant automatically Given, ∫tan-1⁡(x)dx Putting, x = tan(y), We get, dy = sec2(y)dy, ∫ysec2(y)dy By integration by parts, ytan(y) – log⁡(sec⁡(y)) = xtan-1 (x) – 1⁄2 ln⁡(1 + x2).

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∫tan xdx = ?