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The nth derivative of x2y2 + (1-x2)y1 + xy = 0 is,

The nth derivative of x2y2 + (1-x2)y1 + xy = 0 is, Correct Answer x2yn+2 + yn+1(2nx+1-x2) + yn(2n2-2n-2nx+x)-yn – 1(2n2-3n)=0

x2y2 + (1-x2)y1 + xy = 0 Differentiating n times by Leibniz Rule x2yn+2 + 2nxyn+1 + 2n(n-1)yn + (1-x2)yn+1 – 2nxyn – 2n(n-1)yn-1 + xyn + nyn-1 = 0 x2yn+2 + yn+1(2nx+1-x2) + yn(2n2-2n-2nx+x) – yn-1(2n2-3n)=0.

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