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On multiplying (x5 + x2 + x) by (x7 + x4 + x3 + x2 + x) in GF(28) with irreducible polynomial (x8 + x4 + x3 + x + 1) we get

On multiplying (x5 + x2 + x) by (x7 + x4 + x3 + x2 + x) in GF(28) with irreducible polynomial (x8 + x4 + x3 + x + 1) we get Correct Answer x5+x3+x2+x+1

Multiplication gives us (x12 + x7 + x2) mod (x8 + x4 + x3 + x + 1). Reducing this via modular division gives us, (x5+x3+x2+x+1)

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