In a shop, the cost of 5 shirt , 5pairs of trousers and 3 hats is tk.710. The cost of 11shirts , 11pairs of trousers and 8 hats is tk. 1590. What is the total cost of 1 shirt,1 pair of trouser and 1 hat?

In a shop, the cost of 5 shirt , 5pairs of trousers and 3 hats is tk.710. The cost of 11shirts , 11pairs of trousers and 8 hats is tk. 1590. What is the total cost of 1 shirt,1 pair of trouser and 1 hat? Correct Answer Tk. 150

5 shirt , 5 pairs of trousers and 3 hats = 710 TK - - - - - (i) Now, multiplying both sides by 2, 10 shirt , 10 pairs of trousers and 6 hats = 1420 TK  - - - - - - - (ii) Again, 11 shirt , 11 pairs of trousers and 8 hats = 1590 TK  - - - - - - (iii) Now,  {(iii) - (ii)}>> 1 shirt , 1 pair of trousers and 2 hats = 170 TK - - - - - (iv) {(iii)×5}>>   5 shirt , 5 pairs of trousers and 10 hats = 850 TK - - - - - - (v) Now,  {(v) - (i)}>>  7 hats = 140 TK So,  1 hat = 140/7 = 20 TK From (iv),   1 shirt , 1 pair of trousers and 1 hat = 170 - 20 =  150 TK 

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The primitive translation vectors of the body centred cubic lattice are $$\overrightarrow {\bf{a}} = \frac{a}{2}\left( {{\bf{\hat x}} + {\bf{\hat y}} - {\bf{\hat z}}} \right),\,\overrightarrow {\bf{b}} = \frac{a}{2}\left( { - {\bf{\hat x}} + {\bf{\hat y}} + {\bf{\hat z}}} \right)$$        and $$\overrightarrow {\bf{c}} = \frac{a}{2}\left( {{\bf{\hat x}} - {\bf{\hat y}} + {\bf{\hat z}}} \right)$$    . The primitive translation vectors $$\overrightarrow {\bf{A}} ,\,\overrightarrow {\bf{B}} $$  and $$\overrightarrow {\bf{C}} $$ of the reciprocal lattice are