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What will be output of the following c program ? #include int main() { int max-val=100; int min-val=10; int avg-val; avg-val =( max-val + min-val ) / 2; printf( "%d", avg-val ); return 0; }
What is the output of following program? abstract class Sum { public abstract int sumOfTwo(int n1, int n2); public abstract int sumOfThree(int n1, int n2, int n3); public void disp( ){ System.out.println("Method of class Sum"); } } class DemoAbstract1 extends Sum { public int sumOfTwo(int num1, int num2) { return num1+num2; } public int sumOfThree(int num1, int num2, int num3) { return num1+num2+num3; } public static void main(String args[ ]){ Sum obj = new DemoAbstract1( ); System.out.println(obj.sumOfTwo(3, 7)); System.out.println(obj.sumOfThree(4, 3, 19)); obj.disp( ); } }
The void longjmp( jmp-buf env, int val) function causes setjmp() macro to return . . . . . . . . value; if val is 0.
Which two classes use the Shape class correctly?
A. public class Circle implements Shape { private int radius; }B. public abstract class Circle extends Shape { private int radius; }C. public class Circle extends Shape { private int radius; public void draw(); }D. public abstract class Circle implements Shape { private int radius; public void draw(); }E. public class Circle extends Shape { private int radius; public void draw() { /* code here */ } }F. public abstract class Circle implements Shape { private int radius; public void draw() { /* code here */ } }
Which of the given statement is not true with respect to void longjmp( jmp-buf env, int val)?
What is the output of this program ? #include
using namespace std;
int n(char, int);
int (*p) (char, int) = n;
int main()
{
(*p)('d', 9);
p(10, 9);
return 0;
}
int n(char c, int i)
{
cout << c << i;
return 0;
}
What will be the final values of i and j in the following C code?
#include int x = 0;int f(){ if (x == 0) return x + 1; else return x - 1;}int g(){ return x++;}int main(){ int i = (f() + g()) | g(); //bitwise or int j = g() | (f() + g()); //bitwise or}
What will be the final values of i and j in the following C code?
#include int x = 0;int f(){ if (x == 0) return x + 1; else return x - 1;}int g(){ return x++;}int main(){ int i = (f() + g()) || g(); int j = g() || (f() + g());}
Consider the following C function in which size is the number of elements in the array E: int MyX(int *E, unsigned int size) {       int Y = 0;       int Z;       int i, j, k;       for(i = 0; i < size; i++) Y = Y + E[i];       for(i = 0; i < size; i++) for(j = i; j < size; j++) {       Z = 0;       for(k = i; k <= j; k++) Z = Z + E[k];       if (Z > Y) Y = Z; }       return Y; } The value returned by the function MyX is the
What will the following C statement do?
#include < setjmp.h >int setjmp(jmp_buf env);