What is the time complexity of the code that uses merge sort for determining the number of inversions in an array?

What is the time complexity of the code that uses merge sort for determining the number of inversions in an array? Correct Answer O(n log n)

The code of merge sort is slightly modified in order to calculate the number of inversions in an array. So the time complexity of merge sort remains unaffected and hence the time complexity is O(n log n).

Related Questions

A teacher asked the class to subtract 5 from 75.70% of the class said: 25. Their work was shown as: \(\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} 7&5 \end{array}}\\ {\underline {\begin{array}{*{20}{c}}\ { - 5} \ \ \ &{} \end{array}} }\\ {\underline {\begin{array}{*{20}{c}} 2&5 \end{array}} } \end{array}\) Which of the following describes the most appropriate remedial action that the teacher should take to clarify this misconception?