Find the reliability of the system having fours units in series with failure rates of 0.001, 0.002, 0.003, and 0.004 for the total operation of 100 hours.
Find the reliability of the system having fours units in series with failure rates of 0.001, 0.002, 0.003, and 0.004 for the total operation of 100 hours. Correct Answer 0.366
Given, a system with fours unit in series each has failure rates as 0.001, 0.002, 0.003, and 0.004. Therefore, the reliability of each unit is calculated as below: R = e-λt; λ = Failure rate R1 = e-0.001 × 100 = 0.904 R2 = e-0.002 × 100 = 0.818 R3 = e-0.003 × 100 = 0.740 R4 = e-0.004 × 100 = 0.670 As all the units are in series, Reliability of the system = 0.904 × 0.818 × 0.740 × 0.670 = 0.366
