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A tap can fill a tank in 6hours.After half hour the tank filled ,three more similar taps are opened.What is the total time taken to fill the tank completely?

A tap can fill a tank in 6hours.After half hour the tank filled ,three more similar taps are opened.What is the total time taken to fill the tank completely? Correct Answer 4hrs

A tap in 6 hours can fill 1 portion A tap in 1 hours can fill 1/6 portion By 1st 1/2 portion is filled by 3 hours The left 1/2 portion is filled by 3 same tap Now, By 1 tap 1/6 portion is filled in 1 hours By. 3 tap 3/6 portion is filled in 1 hours or 1/2 portion is filled in 1 hours So, total required time is = (3 + 1) hours = 4 hours

Related Questions

Given below are quantities named A,B and C. Based on the given information, you have to determine the relation between the quantities. You should use the given data and your knowledge of mathematics to choose among the possible answer. Quantity A: Tap1 and Tap2 can fill the tank in 16 hours and 25 hours respectively. Both the taps opened together. After some time Tap 1 is closed and after that the tank is filled in 12 hours. In how many hour Tap 1 and 2 work together? Quantity B: Three taps 1, 2, 3 can fill a cistern in 10,14,18 hours respectively. If tap 1 is kept open all the time and tap 2 and 3 is opened alternatively for an hour then find in how many hours the tank will be filled? Quantity C: Two taps 1 and 2 are such that tap 1 fills the tank in 10 hours and tap2 empties it in 20 hours. If tap 1 is opened first and after 5 hours tap 1 is closed and tap 2 is opened, then the tank emptied in x hours and find the value of x?
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