In a CE transmitter amplifier, if the amplification factor is 150 and the collector voltage is 4 V and resistance is 2 kΩ, what should be the value of RB, given that the dc base current is 10 times the signal current?

In a CE transmitter amplifier, if the amplification factor is 150 and the collector voltage is 4 V and resistance is 2 kΩ, what should be the value of RB, given that the dc base current is 10 times the signal current? Correct Answer 20 kΩ

Here, the output voltage is 4 V. So, ic = 4/2000 = 2 mA The signal current through the base, IB = ic/β = 0.013 mA The dc base current = 0.13 mA Assuming here, that VBE = 1.4 V, we get RB = (4.0-1.4)/0.13 = 20 kΩ.
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