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Two monatomic ideal gases 1 and 2 of molecular masses M1 and M2 respectively are enclosed in separate containers kept at the same temperature. The ratio of the speed pf spund in gas 1 to that in gas 2 is given by?

Two monatomic ideal gases 1 and 2 of molecular masses M1 and M2 respectively are enclosed in separate containers kept at the same temperature. The ratio of the speed pf spund in gas 1 to that in gas 2 is given by? Correct Answer √(M2/M1)

v=√(3RT/M) v1/v2 = √(M2/M1).

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