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The latent heat of vaporisation of water is 2,240 J. If the work done in the process of vaporisation of 1g is 168 J, then the increase in internal energy is?

The latent heat of vaporisation of water is 2,240 J. If the work done in the process of vaporisation of 1g is 168 J, then the increase in internal energy is? Correct Answer 2072 J

From the first law of thermodynamics, dQ = mL = dU + dW dU = m L – dW = 1×2240-168 dU = 2072 J.

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