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Two wires have the same material and have the same volume. However wire 1 had cross sectional area A and wire 2 has cross sectional area 3A. If the length of wire 1 increases by ∆x on applying force F, how much force is needed to stretch wire 2 by the same amount?

Two wires have the same material and have the same volume. However wire 1 had cross sectional area A and wire 2 has cross sectional area 3A. If the length of wire 1 increases by ∆x on applying force F, how much force is needed to stretch wire 2 by the same amount? Correct Answer 9F

Y=F/A l/∆l=F/A2 Al/∆x=FV/(A2 ∆x) F=Y∆x/V A2 FαA2 F‘=(3A)2 F‘/F=9 F‘=9F.

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