A body of mass 2kg begins to slide down a plane inclined at an angle of 45° with the horizontal. The force of friction will be?

A mass of 4kg rests on a horizontal plane. The plane is gradually inclined until at an angle θ= 15° with the horizontal, the mass just begins to slide. What is the coefficient of static friction between the block and the surface?

A

0.814

B

0.27

C

1.5

D

3.5

When a body resting on an inclined surface just begins to slide down the inclined plane under the action of its own weight, then the angle of inclination of the inclined plane is

A

Greater than the angle of repose

B

Less than the angle of repose

C

Equal to the angle of repose

D

Vertical

E

Horizontal

A body is resting on a plane inclined at angle 30° to horizontal. What force would be required to slide it down, if the coefficient of friction between body and plane is 0.3?

A

Zero

B

1 kg

C

5 kg

D

10 kg

E

None of these

Which of the following is NOT true about Frictional force? A. Friction is the force which opposes the relative motion of two surfaces in contact. B. The force of friction that acts when a body is moving (sliding) on a surface is called sliding friction. C. Friction in machines wastes energy and also causes wear and tear. D. Rolling friction is much more than sliding friction, the use of ball bearings in a machine considerably reduces friction.

A

D

B

A

C

D

B

A body of mass 10 kg is initially stationary on a 45° inclined plane as shown in figure. The coefficient of dynamic friction between the body and the plane is 0.3. The body slides down the plane and attains a velocity of 20 m/s. The distance travelled (in metre) by the body along the plane is close to

A

4.8

B

98

C

41

D

9.8

A smooth plane inclined at an angle θ with the horizontal as shown in the given figure. A body starts from rest and slides down on the inclined surface. The time taken by the body to reach the bottom is
Gravitational Force mcq question image

A

$$\frac{{\sqrt {2h} }}{g}$$

B

$$\sqrt {\frac{{2l}}{g}} $$

C

$$\frac{1}{{\sin \theta }}\sqrt {\frac{{2h}}{g}} $$

D

$$\sin \theta \frac{{\sqrt {2h} }}{g}$$

A body of weight 100 N is placed on a rough horizontal plane. What will be the co-efficient of friction between surfaces if a horizontal force of 60 N just causes the body to slide over the horizontal plane ?

A

0.3

B

0.4

C

0.5

D

0.6

This are the following statements given regarding satellite’s motion a. A satellite in geostationary orbit lies in the same plane with equator b. A satellite in geosynchronous orbit lies in the same plane with equator c. A satellite in geostationary orbit does not lie in the same plane with equator, it is inclined at some angle from plane of equator d. A satellite in geosynchronous orbit does not lie in the same plane with equator, it is inclined at some angle from plane of equator Choose one of the following options

A

Both option a and b are correct

B

Both option a and c are correct

C

Both option a and d are correct

D

Both option b and c are correct

A body of weight ‘w’ placed on an inclined plane is acted upon by a force ‘P’ parallel to the plane which causes the body just to move up the plane. If the angle of inclination of the plane is ‘θ’ and angle of friction is ‘φ’, the minimum value of ‘P’, is

A

w sin (φ - θ)/cos φ

B

w sin (θ - φ)/cos φ

C

w cos (θ + φ)/cos φ

D

w sinθ cos(θ - φ)/sin φ

A body of weight w placed on an inclined plane is acted upon by a force P parallel to the plane which causes the body just to move up the plane. If the angle of inclination of the plane is $$\theta $$ and angle of friction is $$\varphi $$, the minimum value of P, is

A

$$\frac{{{\text{w}}\sin \left( {\varphi - \theta } \right)}}{{\cos \varphi }}$$

B

$$\frac{{{\text{w}}\sin \left( {\theta - \varphi } \right)}}{{\cos \varphi }}$$

C

$$\frac{{{\text{w}}\cos \left( {\theta + \varphi } \right)}}{{\cos \varphi }}$$

D

$$\frac{{{\text{w}}\sin \theta \cos\left( {\theta - \varphi } \right)}}{{\sin\varphi }}$$

A body of mass 2kg begins to slide down a plane inclined at an angle of 45° with the horizontal. The force of friction will be?

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