A particle moves in a straight-line OA; the distance of the particle from O at time t seconds is x ft, where x = a + bt + ct2 (a, b > 0). What is the meaning of the constant b?
A particle moves in a straight-line OA; the distance of the particle from O at time t seconds is x ft, where x = a + bt + ct2 (a, b > 0). What is the meaning of the constant b? Correct Answer Initial velocity
We have, x = a + bt + ct2 ……….(1) Let, v and f be the velocity and acceleration of a particle at time t seconds. Then, v = dx/dt = d(a + bt + ct2)/dt = b + ct ……….(2) Now from (2) we get v = b, when t = 0. Hence b represents the initial velocity of the particle.
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Feb 20, 2025