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What is the molar solubility product for V3(PO4)5 in terms of KSP?

What is the molar solubility product for V3(PO4)5 in terms of KSP? Correct Answer S = (KSP/84375)1/8

The dissociation reaction is represented as V3(PO4)5 → 3V5+ + 5PO43- If S is the solubility of V5+ and PO43- ions then KSP = 3 5, where the square brackets indicate the molar concentrations of the ions in the solution. KSP can then be written as KSP = 3 5 = 33 x 55 x S8 gives KSP= 84375 x S8. Therefore, on rearranging, S = (KSP/84375)1/8.

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